Answer:B Explanation: A can finish his work in 30 days B can finish his work in 40 days Therefore A’s one day’s work = 1 30 B’s one day’s work = 1 40 (A+B)’s one day’s work = 1 30 + 1 40 4+3 120 = 7 120 Number of days required for A and B to finish the work = 1 ( 7 120 ) = 120 7 =17 1 7 days

Answer:C Explanation:Given (A+B)’s one day’s work = 1 8 (B+C)’s one day’s work = 1 12 (A+B+C) ‘s 1 day’s work = 1 6 Work done by A, alone= (A+B+C) ‘s 1 day’s work - (B+C)’s one day’s work = 1 6 – 1 12 = 2−1 12 = 1 12 Work done by C, alone = (A+B+C) ‘s 1 day’s work - (A+B)’s one day’s work = 1 6 – 1 8 = 4−3 24 = 1 24 ⇒ (A+C)’s one day’s work = 1 12 + 1 24 = 2+1 24 = 3 24 = 1 8 ⇒ (A+C) will take 8 days to complete the work together.

Two pipes can fill the cistern in 10hr and 12 hr respectively, while the third empty it in 20hr. If all pipes are opened simultaneously, then the cistern will be filled in

Answer:A Explanation: Work done by all the tanks working together in 1 hour. ⇒ 1 10 + 1 12 − 1 20 = 2 15 Hence, tank will be filled in 15 2 = 7.5 hour.

Mr. Ram is on tour and he has Rs 360 for his expenses. If he exceeds his tour by 4 days he must cut down daily expenses by Rs 3. The number of days of Mr. Ram's tour programme is

Answer:D Explanation: Let Ram under takes a tour of x days. Then, expenses for each day = 360 x . ⇒ 360 x+4 = 360 x –3 ⇒ x=20 and −24 Hence, x= 20 days.

A and B together can complete a piece of work in 35 days while A alone can complete the same work in 60 days. B alone will be able to complete the same working in:

Answer:C Explanation:a b – c d = ad−cb bd A and B finish one work with company = 35 days ⇒ (A + B)’s one day’s work = 1 35 A alone finish the same work = 60 days ⇒ A’s one day’s work = 1 60 ⇒ B’s one day’s work = (A + B)’s one day’s work - A’s one day’s work = 1 35 – 1 60 (take LCM) = 12−7 420 = 5 420 = 1 84 ⇒ B alone can complete the work in 84 days