Answer:D Explanation: In this type of questions, first we need to calculate 1 hours work, then their collective work as, A's 1 hour work is 1/8 B's 1 hour work is 1/10 (A+B)'s 1 hour work = 1/8 + 1/10 = 9/40 So both will finish the work in 40/9 hours = [Math Processing Error]

A and B can together complete a piece of work in 4 days. If A alone can complete the same work in 12 days, in how many days can B alone complete that work ?

Answer:C Explanation: (A+B)'s 1 day work = 1/4 A's 1 day work = 1/12 B's 1 day work = [Math Processing Error] So B alone can complete the work in 6 days

Answer:B Explanation:Firstly we will find 1 day work of both A and B, then by adding we can get collective days for them, So, A's 1 day work = 1/10 B's 1 day work = 1/15 (A+B)'s 1 day work = [Math Processing Error] So together they can complete work in 6 days.

A can finish a work in 18 days and B can do same work in half the time taken by A. then working together, what part of same work they can finish in a day

Answer:B Explanation: Please note in this question, we need to answer part of work for a day rather than complete work. It was worth mentioning here because many do mistake at this point in hurry to solve the question So lets solve now, A's 1 day work = 1/18 B's 1 day work = 1/9 [because B take half time than A] (A+B)'s one day work = [Math Processing Error] So in one day 1/6 work will be done.

Answer:C Explanation:Whole work will be done by X in 10*4=40 days. Whole work will be done by Y in (40*100/40)=100 days. Whole work will be done by Z in (13*3)=39 days Therefore,Z will complete the work first.