Two stations A and B are 110 km apart on a straight line. One train starts from A at 7 a.m. and travels towards B at 20 kmph. Another train starts from B at 8 a.m. and travels towards A at a speed of 25 kmph. At what time will they meet?
Answer:B Explanation: Suppose they meet x hours after 7 a.m. Distance covered by A in x hours = 20x km. Distance covered by B in (x - 1) hours = 25(x - 1) km. Therefore 20x + 25(x - 1) = 110 => 45x = 135 => x = 3. So, they meet at 10 a.m.
Two trains 200 m and 150 m long are running on parallel rails at the rate of 40 kmph and 45 kmph respectively. In how much time will they cross each other, if they are running in the same direction ?
Two, trains, one from Howrah to Delhi and the other from Delhi to Howrah, start simultaneously. After they meet, the trains reach their destinations after 9 hours and 16 hours respectively. The ratio of their speeds is:
Answer:B Explanation: Speed of the train relative to man =(110 / 6 ) m/sec = (110 / 6 x 18 /5) km/hr = 66 km/hr Speed of the train be x kmph Relative Speed =(x + 6 ) kmph. = x + 6 = 66 x = 60.
Answer:B Explanation: Formula: Distance = Speed * Time If we convert Kmph in to Mpsec multiply by 5/18, 400 = 72 KmpH * time 400 = 72*5/18 * time Time = 20Sec