A train of length 110 meter is running at a speed of 60 kmph. In what time, it will pass a man who is running at 6 kmph in the direction opposite to that in which the train is going?
Answer:C Explanation:Distance = 110 m Relative speed = 60 + 6 = 66 kmph (Since both the train and the man are in moving in opposite direction) = (66*5/18 )m/sec = (55/3 )m/sec Time taken to pass the man = 10*3/55= 6 s
How many seconds will a 500 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
Answer:C Explanation: Distance = 500 m Speed of the train relative to man= ( 63 - 3 ) km/hr = 60 km/hr = (60*5/18) m/s =(50/3) m/s Time taken to pass the man = distance/speed = (500*3/50)sec = 30 sec
A train is traveling at 48 kmph . It crosses another train having half of its length , traveling in opposite direction at 42 kmph, in 12 seconds. It also passes a railway platform in 45 seconds. What is the length of the platform ?
Answer:B Explanation:Speed of train 1 = 48 kmph Let the length of train 1 = 2x meter Speed of train 2 = 42 kmph Length of train 2 = x meter (because it is half of train 1's length) Distance = 2x + x = 3x Relative speed= 48+42 = 90 kmph = (90*5/18)m/s = 25 m/s Time = 12 s Distance/time = speed =3x/12=25 =X=25*12/3 =x=100m Length of the first train = 2x = 200 meter Time taken to cross the platform= 45 s Speed of train 1 = 48 kmph = 480/36 = 40/3 m/s Distance = 200 + y [where y is the length of the platform] 200+y=45*40/3 y=400m
Two trains 137 metres and 163 metres in length are running towards each other on parallel lines, one at the rate of 42 kmph and another at 48 kmpb. In what time will they be clear of each other from the moment they meet?
General Exercise
